CSEC Mathematics · January 2015 · Paper 2 · Question 9(b)(iii)
State the equation of the axis of symmetry of the function f(x) = 3x² + 6x - 2.
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Practise this questionOther parts of this question
- 9(a)(i)Evaluate f(7).[1 mark]
- 9(a)(ii)Write an expression, in terms of x, for f⁻¹(x).[2 marks]
- 9(a)(iii)Write an expression, in terms of x, for fg(x).[2 marks]
- 9(b)(i)Express the quadratic function f(x) = 3x² + 6x - 2, in the form a(x + h)² + k, where a, h and k are constants.[3 marks]
- 9(b)(ii)Hence, or otherwise, state the minimum value of f(x) = 3x² + 6x - 2.[1 mark]
- 9(b)(iv)Sketch the graph of y = 3x² + 6x - 2, showing on your sketch a) the intercept on the y-axis b) the coordinates of the minimum point.[4 marks]
More practice: the rest of this paper · more Axis of Symmetry and Max/Min Values (Quadratic Functions) questions · all CSEC Mathematics past papers