CSEC Mathematics · May/June 2013 · Paper 1 · Question Q27
If x = 4 and y = 2, what is the value of \frac{x^2 + 3y}{xy}
- (A)
1\frac{3}{4} - (B)
2\frac{1}{2} - (C)
2\frac{3}{8} - (D)
2\frac{3}{4}
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