5 marksSeries
CAPE Pure Mathematics Unit 2 · May/June 2013 · Paper 2 · Question 3(b)(i)b)
Show that \sum_{k=1}^n \left( \frac{1}{k^2} - \frac{1}{(k+1)^2} \right) = 1 - \frac{1}{(n+1)^2}.
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