CAPE Pure Mathematics Unit 1 · May/June 2014 · Paper 1 · Question Q32
\lim_{x \to -5} \frac{x + 5}{x^2 - 25} =
- (A)
-\frac{1}{5} - (B)
-\frac{1}{10} - (C)
0 - (D)
\frac{1}{10}
The answer is shown once you've answered.
Practise this question\lim_{x \to -5} \frac{x + 5}{x^2 - 25} =
-\frac{1}{5}-\frac{1}{10}0\frac{1}{10}The answer is shown once you've answered.
Practise this questionMore practice: the rest of this paper · more Limits questions · all CAPE Pure Mathematics Unit 1 past papers