OPR, OQS and TPQ are straight lines such that OP = PR, OS = 3OQ, and QT = 4QP. \vec{OQ} = \mathbf{v} and \vec{OP} = \mathbf{u}.
Use the results of (d) and (f) above to prove that S, R and T lie in a straight line.
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Practise this question\vec{AC}.[2 marks]\vec{AC}.[2 marks]\vec{AC}.[1 mark]\vec{OR} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[1 mark]\vec{OS} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[1 mark]\vec{QP} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[1 mark]\vec{SR} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[2 marks]\vec{OT} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[2 marks]\vec{ST} in its simplest form in terms of \mathbf{u} and/or \mathbf{v}.[1 mark]More practice: the rest of this paper · more Vector Geometry Problems questions · all CSEC Mathematics past papers