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7 marksSolving Mixed Systems of Equations

CSEC Mathematics · 2003 (Specimen) · Paper 2 · Question 9(a)

Solving quadratic and linear equations.

Solve the pair of simultaneous equations: 2x^2 + 4x + y = 0 and y - 3x = -15.

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Other parts of this question

  1. 9(b)By simplifying, show that (2x + 3)^2 - (x + 4)(x - 4) = 3x^2 + 12x + 25.[3 marks]
  2. 9(c)Write 3x^2 + 12x + 25 in the form a(x + h)^2 + k where a, h and k are real numbers. Hence, or otherwise, solve the equation 3x^2 + 12x + 25 = 40.[5 marks]

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