CAPE Pure Mathematics Unit 1 · May/June 2014 · Paper 1 · Question Q26
The variable point P(x, y) moves so that it is the same distance from the points (1, 6) and (3, 2). The equation of the locus of P may be obtained from
- (A)
\frac{y - 6}{x - 1} = \frac{y - 2}{x - 3} - (B)
\frac{x - 1}{y - 6} = \frac{x - 3}{y - 2} - (C)
\sqrt{(x - 1)^2 + (y - 6)^2} = \sqrt{(x - 3)^2 + (y - 2)^2} - (D)
(x - 1) + (y - 6) = (x - 3) + (y - 2)
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