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CSEC Mathematics · January 2011 · Paper 2 · Question 5(a)(ii)

The equation of a straight line is given by: 3y = 2x - 6.

Determine the equation of the line which is perpendicular to 3y = 2x - 6, and passes through the point (4,7).

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Other parts of this question

  1. 5(a)(i)Determine the gradient of the line.[2 marks]
  2. 5(b)(i)Calculate the value of k.[2 marks]
  3. 5(b)(ii)Calculate the value of f(3).[2 marks]
  4. 5(b)(iii)Calculate the value of x when f(x) = 95.[2 marks]

More practice: the rest of this paper · more Parallel and Perpendicular Lines questions · all CSEC Mathematics past papers