CAPE Pure Mathematics Unit 1 · May/June 2012 · Paper 1 · Question Q19
The point P has position vector \begin{pmatrix} -3 \\ 5 \end{pmatrix} and Q is a point such that \vec{PQ} = \begin{pmatrix} 1 \\ -7 \end{pmatrix}. The position vector of Q is
- (A)
\begin{pmatrix} 4 \\ -12 \end{pmatrix} - (B)
\begin{pmatrix} 4 \\ 12 \end{pmatrix} - (C)
\begin{pmatrix} 2 \\ 2 \end{pmatrix} - (D)
\begin{pmatrix} -2 \\ -2 \end{pmatrix}
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