CAPE Physics Unit 1 · 2013 · Paper 1 · Question Q34

In an electrical method for determining the specific heat capacity of a metal, the following readings were obtained: Mass of metal: 2\text{ kg} Supply voltage: 240\text{ V} Current: 3\text{ A} Time for which heat supplied: 20\text{ s} Temperature rise of metal: 10\ ^\circ\text{C} What is the specific heat capacity of the metal?

1. (A)\frac{240 \times 3 \times 6}{2 \times 10 \times 20}\text{ J kg}^{-1}\text{K}^{-1}
2. (B)\frac{2 \times 10 \times 20}{240 \times 3 \times 60}\text{ J kg}^{-1}\text{K}^{-1}
3. (C)\frac{2 \times 10 \times 20}{240 \times 3}\text{ J kg}^{-1}\text{K}^{-1}
4. (D)\frac{240 \times 3 \times 20}{2 \times 10}\text{ J kg}^{-1}\text{K}^{-1}