CSEC Additional Mathematics · May/June 2017 · Paper 1 · Question Q13
\sqrt[n]{3 \times 27^m} is equal to
- (A)
3^{\frac{3m+1}{n}} - (B)
3^{n+3m} - (C)
\sqrt[n]{81^{3m}} - (D)
3^{\frac{4m}{n}}
The answer is shown once you've answered.
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