CSEC Mathematics · January 2011 · Paper 1 · Question Q26
3a(a+2b) - b(2a-3b) =
- (A)
3a^2 - ab + 3b^2 - (B)
3a^2 + 4ab + 3b^2 - (C)
3a^2 + 4ab - 3b^2 - (D)
3a^2 + 8ab - 3b^2
The answer is shown once you've answered.
Practise this question3a(a+2b) - b(2a-3b) =
3a^2 - ab + 3b^23a^2 + 4ab + 3b^23a^2 + 4ab - 3b^23a^2 + 8ab - 3b^2The answer is shown once you've answered.
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