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CAPE Physics Unit 1 · May/June 2025 · Paper 2 · Question 2(d)(i)

A photographer takes a picture of a 1.7 m tall person standing 2.5 m in front of a camera using a converging lens of focal length 0.05 m.

Calculate the image distance of the person.

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Other parts of this question

  1. 2(a)(i)Name the process by which the human eye adjusts its focus to see objects clearly at varying distances.[1 mark]
  2. 2(a)(ii)Complete Table 1 by describing myopia, hypermetropia, and astigmatism, stating the cause and the corrective lens needed for each.[9 marks]
  3. 2(b)Plot a graph of magnification M versus image distance v on the axes in Figure 2, and draw the line of best fit.[3 marks]
  4. 2(c)(i)Use the graph on page 11 to determine the focal length, f, of the mirror given that M = 1 - v/f.[5 marks]
  5. 2(c)(ii)Use the graph to determine the image distance when the magnification M = 0.6.[1 mark]
  6. 2(d)(ii)Calculate the magnification AND the height of the image on the film of the camera.[5 marks]
  7. 2(d)(iii)Based on your results from (d)(i) and (ii), comment on the nature of the image formed on the film.[2 marks]

More practice: the rest of this paper · more Physics of the Ear and Eye questions · all CAPE Physics Unit 1 past papers