CSEC Additional Mathematics · 2018 · Paper 1 · Question Q40
\int_0^2 (3x + 4)^3 \,\mathrm{d}x =
- (A)
812\text{ units}^2 - (B)
821\text{ units}^2 - (C)
830\text{ units}^2 - (D)
854\frac{2}{3}\text{ units}^2
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