CSEC Additional Mathematics · May/June 2017 · Paper 1 · Question Q6
The set of values of x for which \frac{5x - 2}{2 - 3x} \ge 0 is given by
- (A)
\left\{x : x \ge \frac{2}{5} \cup x > \frac{2}{3}\right\} - (B)
\left\{x : x \le \frac{2}{5} \cup x > \frac{2}{3}\right\} - (C)
\left\{x : \frac{2}{3} < x \le \frac{2}{5}\right\} - (D)
\left\{x : \frac{2}{5} \le x < \frac{2}{3}\right\}
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