CSEC Additional Mathematics · 2018 · Paper 1 · Question Q9
If f : x \to 2\left(\frac{x}{3} + 5\right), then f^{-1}(x) is equal to
- (A)
3\left(\frac{x}{2} - 5\right) - (B)
3\left(\frac{x}{2} + 5\right) - (C)
\frac{1}{3}\left(\frac{x}{2} - 5\right) - (D)
\frac{3(x - 2)}{5}
The answer is shown once you've answered.
Practise this question