CAPE Chemistry Unit 2 · 2016 · Paper 1 · Question Q20
In an electronic transition in the UV/visible region of the spectrum, a wavelength of 450 nm is absorbed.
Planck constant (h) = 6.63 \times 10^{-34}\text{ J s}
Velocity of light (c) = 3.00 \times 10^8\text{ m s}^{-1}
The energy of the corresponding photon (in Joules) is
- (A)
\frac{66.3 \times 10^{-34} \times 10^8}{4.50 \times 10^{-5}} - (B)
\frac{4.50 \times 10^{-7}}{6.63 \times 10^{-34} \times 3 \times 10^8} - (C)
\frac{6.63 \times 10^{-34} \times 3 \times 10^8}{4.50 \times 10^{-9}} - (D)
\frac{6.63 \times 10^{-34} \times 3 \times 10^8}{4.50 \times 10^{-7}}
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