CSEC Mathematics · January 2017 · Paper 1 · Question Q33
If the circumference of the circle is 15\text{ cm}, then the length of the minor arc AB, in centimetres, is
- (A)
\frac{360}{120} \times 15 - (B)
\frac{120}{360} \times 15 - (C)
\frac{360}{360 - 120} \times 15 - (D)
\frac{360 - 120}{360} \times 15
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