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CSEC Additional Mathematics · 2014 · Paper 2 · Question 4(b)

Given that sin(π/6) = 1/2 and cos(π/6) = √3/2,

show that cos(x + π/6) = (1/2)(√3 cos x - sin x), where x is acute.

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Other parts of this question

  1. 4(a)(i)Find the area of the sector OAB.[2 marks]
  2. 4(a)(ii)Hence, find the area of the shaded region, H.[4 marks]
  3. 4(c)Prove the identity (tan θ sin θ)/(1 - cos θ) = 1 + 1/cos θ.[4 marks]

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