CAPE Pure Mathematics Unit 1 · May/June 2012 · Paper 1 · Question Q25
Given that \alpha is an acute angle and \tan\alpha = \frac{3}{4}, then \sin(90^\circ - \alpha) =
- (A)
\frac{2}{5} - (B)
\frac{3}{5} - (C)
\frac{3}{4} - (D)
\frac{4}{5}
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