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1 markHarmonic Motion

CAPE Physics Unit 1 · 2004 · Paper 2 · Question 7(b)(ii)

A simple pendulum has a length of 2.0 m and a mass of 0.5 kg. It is hanging from the roof of a car that is travelling at 5 m s⁻¹ and banking a corner of radius 15 m.

If the car is now at rest, and the pendulum undergoes S.H.M, would its time period be shorter or longer than that calculated in 7 (b) (i)? Explain your answer.

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Other parts of this question

  1. 7(a)(i)Define 'simple harmonic motion' (S.H.M.) and write down an expression relating acceleration to displacement in S.H.M.[8 marks]
  2. 7(a)(ii)Show that the time period of oscillation, T, of a simple pendulum of length l and mass m is given by T = 2π√(l/g) where g is the acceleration due to gravity.[1 mark]
  3. 7(b)(i)Calculate the time period of oscillation for the pendulum.[6 marks]
  4. 7(c)(i)Determine the angular frequency of this oscillation.[6 marks]
  5. 7(c)(ii)Find the period of this S.H.M.[1 mark]
  6. 7(c)(iii)a)Find at time t = 1.0 s the displacement.[1 mark]
  7. 7(c)(iii)b)Find at time t = 1.0 s the velocity.[1 mark]
  8. 7(c)(iii)c)Find at time t = 1.0 s the acceleration.[1 mark]

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