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CSEC Mathematics · January 2006 · Paper 2 · Question 14(c)(i)

The image, (x', y'), of any point, (x, y), under a transformation N is given by the equation (x'; y') = (2 0; 0 2)(x; y) + (5; -2).

Calculate the image, (x', y'), of (3, -1) under N.

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Other parts of this question

  1. 14(a)(i)Calculate, in terms of x, the determinant of L.[3 marks]
  2. 14(a)(ii)Calculate the values of x given that L is singular.[3 marks]
  3. 14(b)(i)Find M^-1, the inverse of M.[6 marks]
  4. 14(b)(ii)Hence, calculate the value of x and of y for which M(x; y) = (12; -8).[6 marks]
  5. 14(c)(ii)Calculate the coordinates of the point, (x, y), which is mapped by N onto (7, 4).[3 marks]

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