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CAPE Chemistry Unit 2 · 2014 · Paper 2 · Question 1(a)(ii)

Methane reacts with bromine in the presence of UV radiation to form substitution products such as bromomethane.

Write equations to show the steps occurring in the propagation stage for the formation of dibromomethane from bromomethane.

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Other parts of this question

  1. 1(a)(i)State the role of the UV radiation in the reaction.[1 mark]
  2. 1(b)(i)Write the expression for the basic dissociation constant, Kb.[2 marks]
  3. 1(b)(ii)The pKb values for ethylamine and phenylamine are 3.27 and 9.38 respectively. State which of these compounds is the stronger base.[1 mark]
  4. 1(b)(iii)State TWO reasons for the difference between the two pKb values in (b)(ii).[2 marks]
  5. 1(c)(i)Suggest a value for Kb for ethanamide, CH3CONH2.[1 mark]
  6. 1(c)(ii)State a reason for your answer in (c)(i).[1 mark]
  7. 1(d)Complete Table 1 by inserting the appropriate observations for tests (i) to (iv).[5 marks]

More practice: the rest of this paper · more Functional Group Analysis, Reactions and Mechanisms questions · all CAPE Chemistry Unit 2 past papers