CAPE Pure Mathematics Unit 1 · May/June 2014 · Paper 1 · Question Q35
Given that \cos 2x = 2\cos^2 x - 1, then \int \cos^2\left(\frac{x}{4}\right) dx is
- (A)
\frac{1}{2}x + \frac{1}{2}\int \cos 4x\, dx - (B)
\frac{1}{2}x + \int \cos\frac{x}{4}\, dx - (C)
\frac{1}{2}x + \int \cos\frac{x}{2}\, dx - (D)
\frac{1}{2}x + \frac{1}{2}\int \cos\frac{x}{2}\, dx
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