CSEC Mathematics · May/June 2008 · Paper 2 · Question 9(b)(ii)
Hence determine the minimum value of the function y = x^2 - 3x - 12.
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Practise this questionOther parts of this question
- 9(a)Solve the pair of simultaneous equations y = x^2 - 3x - 12 and y = 2x - 16.[4 marks]
- 9(b)(i)Express y = x^2 - 3x - 12 in the form y = (x - h)^2 + k, where h and k are constants.[3 marks]
- 9(b)(iii)Calculate, correct to one decimal place, the roots of the equation x^2 - 3x - 12 = 0.[3 marks]
- 9(c)(i)Sketch the graph of y = x^2 - 3x - 12, showing clearly: the value of x where the function is a minimum.[1 mark]
- 9(c)(ii)Sketch the graph of y = x^2 - 3x - 12, showing clearly: the x-intercepts.[2 marks]
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