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CSEC Physics · January 2015 · Paper 2 · Question 6(b)

One isotope of lead, ²¹⁰₈₂Pb, is not stable but can undergo exactly three distinct decays of an alpha or beta particle to become stable lead. Table 5 provides atomic numbers for Bi (83) and Po (84).

With reference to the information in Table 5, write a possible sequence of three nuclear equations that can result in ²⁰⁶₈₂Pb (stable lead) from ²¹⁰₈₂Pb.

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Other parts of this question

  1. 6(a)(i)Describe the path of each of the three emissions (α, β and γ) when subjected to a uniform electric field from left if the emissions are projected up towards…[3 marks]
  2. 6(a)(ii)If the electric field is replaced by a uniform magnetic field into the page, predict the path of the emissions.[3 marks]
  3. 6(c)Calculate the energy given off in a nuclear reaction if the change in mass is 0.2014 u. (u = 1.66 × 10⁻²⁷ kg; c = 3.0 × 10⁸ ms⁻¹).[3 marks]

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