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2 marksProjectiles

CAPE Applied Mathematics Unit 2 · 2014 · Paper 2 · Question 6(b)(i)

A ball is projected with speed 45 ms⁻¹ at angle α above the horizontal from point A (height 4 m above ground) and lands at B (horizontal distance 90 m from A). Take g = 10 ms⁻².

Show that 20 tan² α – 90 tan α + 16 = 0.

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Other parts of this question

  1. 6(a)Formulate the equation of the trajectory of a projectile.[4 marks]
  2. 6(b)(ii)Hence, find to the nearest degree, the TWO possible values of α.[5 marks]
  3. 6(b)(iii)Find, to the nearest second, the MINIMUM possible time of flight from A to B.[3 marks]
  4. 6(c)Find the value of T.[6 marks]
  5. 6(d)Find the velocity of the particle when s = 3.[5 marks]

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