CSEC Mathematics · January 2011 · Paper 1 · Question Q27
If m * n = \sqrt{mn - n^2}, then 5 * 3 =
- (A)
\sqrt{6} - (B)
3 - (C)
\sqrt{15} - (D)
6
The answer is shown once you've answered.
Practise this questionIf m * n = \sqrt{mn - n^2}, then 5 * 3 =
\sqrt{6}3\sqrt{15}6The answer is shown once you've answered.
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