CAPE Pure Mathematics Unit 2 · May/June 2015 · Paper 1 · Question Q3

Given that \cos 2x = 1 - 2\sin^2 x, then \int_0^{\pi} \sin^2\left(\frac{x}{4}\right) dx is

1. (A)2 - \pi
2. (B)\pi - 2
3. (C)1 - \frac{\pi}{2}
4. (D)\frac{\pi}{2} - 1