CAPE Pure Mathematics Unit 1 · May/June 2009 · Paper 1 · Question Q23
The normal at P(4, 3) to the circle (x - 2)^2 + y^2 = 25 has gradient \frac{3}{4}. The equation of the tangent at P to (x - 2)^2 + y^2 = 25 is
- (A)
y - 3 = \frac{-4}{3}(x - 4) - (B)
y - 3 = \frac{-3}{4}(x - 4) - (C)
y - 4 = \frac{3}{4}(x - 3) - (D)
y - 4 = \frac{-3}{4}(x - 3)
The answer is shown once you've answered.
Practise this question