CSEC Chemistry · May/June 2011 · Paper 1 · Question Q9

When solid lead nitrate is heated, it decomposes giving off nitrogen (IV) oxide and oxygen. The balanced equation for this reaction is

1. (A)2\text{Pb}(\text{NO}_3)_2(\text{s}) \rightarrow 2\text{PbO}(\text{s}) + 4\text{NO}_2(\text{g}) + \text{O}_2(\text{g})
2. (B)\text{Pb}(\text{NO}_3)_2(\text{s}) \rightarrow \text{PbO}(\text{s}) + \text{NO}_2(\text{g}) + \text{O}_2(\text{g})
3. (C)\text{Pb}(\text{NO}_3)_2(\text{s}) \rightarrow \text{PbO}(\text{s}) + 2\text{NO}_2(\text{g}) + \text{O}_2(\text{g})
4. (D)2\text{Pb}(\text{NO}_3)_2(\text{s}) \rightarrow 2\text{PbO}(\text{s}) + 2\text{NO}_2(\text{g}) + \text{O}_2(\text{g})