CAPE Pure Mathematics Unit 1 · 2008 (T&T) · Paper 1 · Question Q31
Given that f(x) = \begin{cases} 3x + 5 & \text{for } x < 3 \\ ax + 2 & \text{for } x \ge 3. \end{cases} For the function to be continuous at x = 3, the value of 'a' should be
- (A)
-3 - (B)
-1 - (C)
4 - (D)
12
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