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1 markSimplifying Vector Expressions

CSEC Mathematics · May/June 2005 · Paper 2 · Question 13(a)(ii)

ABCD is a parallelogram with DC = 3x and DA = 3y. Point P is on DB such that DP : PB = 1:2.

Express in terms of x and y: BD

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Other parts of this question

  1. 13(a)(i)Express in terms of x and y: AB[5 marks]
  2. 13(a)(iii)Express in terms of x and y: DP[1 mark]
  3. 13(b)Show that AP = x - 2y.[2 marks]
  4. 13(c)Prove that A, P and E are collinear.[4 marks]
  5. 13(d)Use a vector method to prove that triangle AED is isosceles.[4 marks]

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