CSEC Additional Mathematics · 2015 · Paper 1 · Question Q31
\sin(\alpha - 45^\circ) is equal to
- (A)
\frac{1}{\sqrt{2}}(\sin\alpha - \cos\alpha) - (B)
\frac{1}{\sqrt{2}}(\cos\alpha - \sin\alpha) - (C)
\frac{1}{2}(\sin\alpha - \cos\alpha) - (D)
\frac{1}{2}(\cos\alpha - \sin\alpha)
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