CSEC Additional Mathematics · 2013 · Paper 1 · Question Q38
If y = \frac{x^2}{x + 3}, then \frac{dy}{dx} is
- (A)
\frac{-3x(x + 2)}{(x + 3)^2} - (B)
\frac{3x(x + 2)}{(x + 3)^2} - (C)
\frac{-x(x + 6)}{(x + 3)^2} - (D)
\frac{x(x + 6)}{(x + 3)^2}
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