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CAPE Physics Unit 2 · 2003 · Paper 1 · Question 9(c)(ii)

An induced fission reaction is described by the equation: 1_0 n + 235_92 U -> 236_92 U* -> 141_56 Ba + 92_36 Kr + 3 1_0 n + E. Masses: 235_92 U = 235.0439 u; 141_56 Ba = 140.9141 u; 92_36 Kr = 91.9262 u; 1_0 n = 1.0087 u; 1 u = 931.5 MeV/c^2.

Calculate the energy, in eV, of EACH neutron produced in the reaction.

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Other parts of this question

  1. 9(a)(i)Explain what is meant by nuclear fission.[1 mark]
  2. 9(a)(ii)Explain what is meant by nuclear fusion.[1 mark]
  3. 9(a)(iii)Explain what is meant by binding energy.[1 mark]
  4. 9(b)(i)How many protons are there in the nucleus?[1 mark]
  5. 9(b)(ii)How many neutrons are there in the nucleus?[1 mark]
  6. 9(c)(i)Calculate the energy E, in eV, released during the reaction.[4 marks]

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