Quelpr

Other parts of this question

  1. 3(a)(i)prove that cos 3θ = 2 cos θ [cos² θ – sin² θ – 1/2].[7 marks]
  2. 3(a)(ii)Using the appropriate formula, show that 1/2 [sin 6θ – sin 2θ] = (2 cos² 2θ – 1) sin 2θ.[5 marks]
  3. 3(a)(iii)Hence, or otherwise, solve sin 6θ − sin 2θ = 0 for 0 ≤ θ ≤ π/2.[5 marks]

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