CAPE Pure Mathematics Unit 2 · May/June 2017 · Paper 1 · Question Q41
A bag contains 6 blue balls and 4 red balls. Terry chooses 2 balls at random from the bag without replacement. The probability that BOTH balls are red is
- (A)
\frac{4}{10} \times \frac{3}{9} - (B)
\frac{6}{10} \times \frac{3}{9} - (C)
\left(\frac{6}{10} \times \frac{4}{9}\right) + \left(\frac{4}{10} \times \frac{3}{9}\right) - (D)
\left(\frac{6}{10} \times \frac{4}{9}\right) \times \left(\frac{4}{10} \times \frac{3}{9}\right)
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