CSEC Mathematics · January 2011 · Paper 1 · Question Q54

In the right-angled triangle above, not drawn to scale, \hat{Q} = 90^\circ, PQ = 50\text{ cm}, PR = 130\text{ cm} and RQ = x\text{ cm}. \text{Tan } P\hat{R}Q =

1. (A)\frac{50}{x}
2. (B)\frac{x}{50}
3. (C)\frac{50}{130}
4. (D)\frac{x}{130}

This question uses a figure or table from the paper — you'll see it when you practise.