CAPE Pure Mathematics Unit 1 · May/June 2009 · Paper 1 · Question Q38
If y = \sqrt{2x + 1} then \frac{d^2y}{dx^2} is
- (A)
\frac{1}{(2x + 1)\sqrt{2x + 1}} - (B)
\frac{-1}{(2x + 1)\sqrt{2x + 1}} - (C)
\frac{1}{\sqrt{2x + 1}} - (D)
\frac{1}{(2x + 1)}
The answer is shown once you've answered.
Practise this question