CAPE Physics Unit 1 · 2008 (T&T) · Paper 1 · Question Q31
On the absolute thermodynamic temperature scale 407.32\text{ }^\circ\text{C} is equivalent to
- (A)
1.49\text{ K} - (B)
134.17\text{ K} - (C)
307.32\text{ K} - (D)
680.47\text{ K}
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