CAPE Pure Mathematics Unit 1 · 2008 (T&T) · Paper 1 · Question Q36
If y = \frac{(x^2 + 8)^4}{3} then \frac{\mathrm{d}y}{\mathrm{d}x} =
- (A)
\frac{8}{3}x(x^2 + 8)^3 - (B)
\frac{8}{3}(x^2 + 8)^3 - (C)
8x(x^2 + 8)^3 - (D)
8(x^2 + 8)^3
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