CAPE Pure Mathematics Unit 1 · 2008 (T&T) · Paper 1 · Question Q11
If |x - 1|^2 + 2|x - 1| = 3, then x is
- (A)
0or2 - (B)
-2or1 - (C)
\frac{1}{2}or1 - (D)
\frac{2}{3}or0
The answer is shown once you've answered.
Practise this questionIf |x - 1|^2 + 2|x - 1| = 3, then x is
0 or 2-2 or 1\frac{1}{2} or 1\frac{2}{3} or 0The answer is shown once you've answered.
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