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CSEC Additional Mathematics · 2014 · Paper 2 · Question 8(b)(ii)

A particle travels along a straight line. It starts from rest at a point, P, on the line and after 10 seconds, it comes to rest at another point, Q, on the line. The velocity v m s⁻¹ at time t seconds after leaving P is v = 0.72t² - 0.096t³ for 0 ≤ t ≤5 and v = 2.4t-0.24t² for 5 ≤ t ≤ 10. At maximum velocity the particle has no acceleration.

Determine the maximum velocity.

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Other parts of this question

  1. 8(a)(i)What distance did the car travel from Point A towards Point B before starting to decelerate?[2 marks]
  2. 8(a)(ii)Calculate the deceleration of the car as it goes from 25 m s⁻¹ to 10 m s⁻¹.[5 marks]
  3. 8(a)(iii)For how long did the car maintain the speed of 10 m s⁻¹?[1 mark]
  4. 8(a)(iv)Determine the average velocity of the car over the journey from Point A to Point C.[2 marks]
  5. 8(b)(i)Find the time when the velocity is at its maximum.[3 marks]
  6. 8(b)(iii)Find the distance moved by the particle from P to the point where the particle attains its maximum velocity.[5 marks]

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