CAPE Pure Mathematics Unit 2 · May/June 2017 · Paper 1 · Question Q6
Given that y = \tan^{-1}(2x), then \frac{dx}{dy} equals
- (A)
\frac{1}{\sqrt{1 - (2x)^2}} - (B)
\frac{1}{\sqrt{1 - x^2}} - (C)
\frac{2}{1 + 4x^2} - (D)
\frac{1 + 4x^2}{2}
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