CSEC Chemistry · May/June 2007 · Paper 2 · Question 4(c)(iii)
Y has the molecular formula, C₄H₁₀.
Draw the fully displayed structure of Y.
The mark scheme is shown once you've answered.
Practise this questionOther parts of this question
- 4(a)Deduce the molecular formula of X.[4 marks]
- 4(b)(i)Based on your answer in 4 (a) on page 9, deduce the homologous series to which X belongs.[1 mark]
- 4(b)(ii)Write the name of Compound X.[1 mark]
- 4(b)(iii)Draw the fully displayed structure of X.[1 mark]
- 4(c)(i)To what homologous series does Y belong?[1 mark]
- 4(c)(ii)Write the name of Compound Y.[1 mark]
- 4(d)What chemical test may be used to distinguish between Compounds X and Y? Reagent: Observation:[2 marks]
- 4(e)What reagent and reaction conditions are necessary to convert Y to X? Reagent: Conditions:[2 marks]
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