CSEC Additional Mathematics · 2015 · Paper 1 · Question Q11
If f : x \rightarrow 2\left(\frac{x}{3} + 5\right), then f^{-1}(x) is equal to
- (A)
\frac{3(x - 2)}{5} - (B)
3\left(\frac{x}{2} - 5\right) - (C)
3\left(\frac{x}{2} + 5\right) - (D)
\frac{1}{3}\left(\frac{x}{2} - 5\right)
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