CSEC Additional Mathematics · 2018 · Paper 1 · Question Q10
If f(x) = \frac{4x + 1}{x - 2}, x \ne 2, x \in \mathbb{R}, then ff(x) =
- (A)
\frac{2x - 1}{-3 - x},x \ne -3,x \in \mathbb{R} - (B)
\frac{2x - 1}{5 - x},x \ne 5,x \in \mathbb{R} - (C)
\left(\frac{x + 2}{x - 2}\right)^2,x \ne 2,x \in \mathbb{R} - (D)
\frac{2x - 1}{3x + 5},x \ne -\frac{5}{3},x \in \mathbb{R}
The answer is shown once you've answered.
Practise this question