CSEC Mathematics · May/June 2005 · Paper 2 · Question 9(b)(i)
Hence, or otherwise, determine the minimum value of the function y = 5x² + 2x - 7.
The mark scheme is shown once you've answered.
Practise this questionOther parts of this question
- 9(a)Write 5x² + 2x - 7 in the form a(x + b)² + c, where a, b, and c are real numbers.[4 marks]
- 9(b)(ii)Hence, or otherwise, determine the value of x at which the minimum occurs.[1 mark]
- 9(c)Find the values of x for which 5x² + 2x - 7 = 0.[3 marks]
- 9(d)(i)Sketch the graph of y = 5x² + 2x - 7, clearly showing the coordinates of the minimum point.[5 marks]
- 9(d)(ii)Sketch the graph of y = 5x² + 2x - 7, clearly showing the value of the y-intercept.[1 mark]
- 9(d)(iii)Sketch the graph of y = 5x² + 2x - 7, clearly showing the points where the graph cuts the x-axis.[1 mark]
More practice: the rest of this paper · more Axis of Symmetry and Max/Min Values (Quadratic Functions) questions · all CSEC Mathematics past papers