CAPE Chemistry Unit 2 · 2015 · Paper 1 · Question Q11
2-hydroxy-2-methylpropanoic acid can be formed from propanone in two steps as illustrated below.
\text{CH}_3-\text{C}(=\text{O})-\text{CH}_3 \xrightarrow{\text{Step X}} \text{CH}_3-\text{C}(\text{OH})(\text{C}\equiv\text{N})-\text{CH}_3 \xrightarrow{\text{Step Y}} \text{CH}_3-\text{C}(\text{OH})(\text{C}(=\text{O})\text{OH})-\text{CH}_3
Which of the following statements about these steps may be true?
I. Step X involves nucleophilic addition.
II. Aqueous potassium cyanide is the reagent in Step X.
III. Step Y involves hydrolysis.
- (A)I only
- (B)I and II only
- (C)II and III only
- (D)I, II and III
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